If the thickness L of a plane wall used for conduction doubles, what happens to the heat transfer rate Q (assuming k, A, ΔT constant)?

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Study for the NANTeL Mechanical Engineering Certification Test. Master the format with quizzes, hints, and explanations designed for exam success. Ready yourself with focused preparation for your certification!

Multiple Choice

If the thickness L of a plane wall used for conduction doubles, what happens to the heat transfer rate Q (assuming k, A, ΔT constant)?

Heat transfer rate through a plane wall in steady conduction is inversely proportional to its thickness. The relation Q = (k A ΔT)/L shows that with k, A, and ΔT fixed, if the thickness L doubles, Q becomes half. So the heat flow rate is halved because the same temperature difference has to push heat through a longer path, reducing the rate of transfer.

If the thickness L of a plane wall used for conduction doubles, what happens to the heat transfer rate Q (assuming k, A, ΔT constant)?

Study for the NANTeL Mechanical Engineering Certification Test. Master the format with quizzes, hints, and explanations designed for exam success. Ready yourself with focused preparation for your certification!

If the thickness L of a plane wall used for conduction doubles, what happens to the heat transfer rate Q (assuming k, A, ΔT constant)?

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