For a Carnot refrigerator operating between hot reservoir at 450 K and cold reservoir at 350 K, COP_R is?

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Multiple Choice

For a Carnot refrigerator operating between hot reservoir at 450 K and cold reservoir at 350 K, COP_R is?

Explanation:
The key idea is how the COP of a Carnot refrigerator is defined and calculated. For a reversible Carnot refrigerator, COP_R equals the heat removed from the cold reservoir divided by the work input, and the relationship is COP_R = T_C / (T_H − T_C), with temperatures in kelvin. Plugging in T_C = 350 K and T_H = 450 K gives COP_R = 350 / (450 − 350) = 350 / 100 = 3.5. That is the standard COP for a Carnot refrigerator between those temperatures. If you see a value like 4.5, that would come from the Carnot heat pump formula COP_HP = T_H / (T_H − T_C) = 450 / 100 = 4.5, which is not the refrigerator’s COP. So the correct refrigerator COP under these conditions is 3.5, and the provided options don’t match that.

The key idea is how the COP of a Carnot refrigerator is defined and calculated. For a reversible Carnot refrigerator, COP_R equals the heat removed from the cold reservoir divided by the work input, and the relationship is COP_R = T_C / (T_H − T_C), with temperatures in kelvin.

Plugging in T_C = 350 K and T_H = 450 K gives COP_R = 350 / (450 − 350) = 350 / 100 = 3.5. That is the standard COP for a Carnot refrigerator between those temperatures.

If you see a value like 4.5, that would come from the Carnot heat pump formula COP_HP = T_H / (T_H − T_C) = 450 / 100 = 4.5, which is not the refrigerator’s COP. So the correct refrigerator COP under these conditions is 3.5, and the provided options don’t match that.

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